This file was generated by AnalyzeEverything (www.norrsken-data-teknik.com)
Note | Leistung [%] | Anzahl | Datum | Martin |
6 | 24.2 | 12 | 2003-06-16 | |
5 | 28.7 | 2 | 2003-06-26 | 5 |
2 | 76.7 | 1 | 2003-06-16 | |
3 | 59.3 | 1 | 2003-06-16 | |
4 | 41.9 | 2 | 2003-06-16 | |
1 | 92.6 | 0 | 2003-06-16 | |
6 | 6 | 2003-06-24 | ||
5 | 2 | 2003-06-24 | 5 | |
4 | 2 | 2003-06-24 | ||
3 | 4 | 2003-06-24 | ||
2 | 2 | 2003-06-24 | ||
1 | 2 | 2003-06-24 | ||
6 | 2 | 2004-05-05 | ||
5 | 1 | 2004-05-05 | ||
4 | 3 | 2004-05-05 | ||
3 | 4 | 2004-05-05 | ||
2 | 4 | 2004-05-05 | ||
1 | 0 | 2004-05-05 |
The data distribution
nmax. class index=18
p0=0.1844
sumΣ Anzahl=50.0
(This has been calculated by the parameters
mean-argNote=4.32
standard-deviationNote=1.6424)
The chi-square test with the
significance level 0.95
(error probability 5.0%)
and the degree of freedom m = n -1
(manually changed the number of classes, class borders)
mNote = 5
(reduced by 2 because the mean-value and the standard-deviation are unknown and hence calculated)
produces the chi-square values
chi2Σ Anzahl = 34.291
chi20.05, 3 = 0.37.
If the condition
chi2Σ Anzahl < chi20.05, 3
is true, the assumption that the distribution is binomial can be accepted.
So the theory, Note is randomly distributed, must be rejected.
Note | Σ Anzahl [%] | Σ Anzahl | estimated: Σ Anzahl |
1.0 | 4.0 | 2.0 | 1.2739 |
2.0 | 14.0 | 7.0 | 5.1858 |
3.0 | 18.0 | 9.0 | 9.9689 |
4.0 | 14.0 | 7.0 | 12.024 |
5.0 | 10.0 | 5.0 | 10.198 |
6.0 | 40.0 | 20.0 | 6.4576 |
The data distribution
nmax. class index=18
p0=0.1844
sumΣ Anzahl=50.0
(This has been calculated by the parameters
mean-argNote=4.32
standard-deviationNote=1.6424)
The assumption is now: The data is not randomly distributed.
The chi-square test with the
significance level 0.95
(error probability 5.0%)
and the degree of freedom m = n -1
(manually changed the number of classes, class borders)
mNote = 5
(reduced by 2 because the mean-value and the standard-deviation are unknown and hence calculated)
produces the chi-square values
chi2Σ Anzahl = 34.291
chi20.95, 3 = 7.82.
If the condition
chi20.95, 3 < chi2Σ Anzahl
is true, the assumption that the distribution is not binomial can be accepted.
So the theory, Note is not randomly distributed, can be accepted.
Note | Σ Anzahl [%] | Σ Anzahl | estimated: Σ Anzahl |
1.0 | 4.0 | 2.0 | 1.2739 |
2.0 | 14.0 | 7.0 | 5.1858 |
3.0 | 18.0 | 9.0 | 9.9689 |
4.0 | 14.0 | 7.0 | 12.024 |
5.0 | 10.0 | 5.0 | 10.198 |
6.0 | 40.0 | 20.0 | 6.4576 |
The data distribution
nmax. class index=18
p0=0.1844
sumΣ Anzahl=50.0
(This has been calculated by the parameters
mean-argNote=4.32
standard-deviationNote=1.6424)
The STUDENT t-test with the
significance level 0.95
(error probability 5.0%)
and the degree of freedom m = n -1
(manually changed the number of classes, class borders)
mNote = 5
produces the t-test values
TΣ Anzahl = 76.677
t0.95, 5 = 2.59.
If the condition
TΣ Anzahl < t 0.95, 5
is true, the assumption that the distribution is binomial can be accepted.
So the theory, Note is randomly distributed, must be rejected.
Note | Σ Anzahl [%] | Σ Anzahl | estimated: Σ Anzahl |
1.0 | 4.0 | 2.0 | 1.2739 |
2.0 | 14.0 | 7.0 | 5.1858 |
3.0 | 18.0 | 9.0 | 9.9689 |
4.0 | 14.0 | 7.0 | 12.024 |
5.0 | 10.0 | 5.0 | 10.198 |
6.0 | 40.0 | 20.0 | 6.4576 |